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Solve for d:  m=n xlog10(d/k)+h 

 

 

Solve for d: a=b2x√d/c - f    (a equals bsquared times square root of d, divided by c minus f) 

 Jan 26, 2016
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Solve for d:  m=n xlog10(d/k)+h

 

Solve for d:
m = h+(log(10) d n x)/k

m = h+(d n x log(10))/k is equivalent to h+(d n x log(10))/k = m:
h+(log(10) d n x)/k = m

Subtract h from both sides:
(log(10) d n x)/k = m-h

Divide both sides by (n x log(10))/k:
Answer: | d = (k m) / (log(10) n x) - (h k) / (log(10) n x)

 

Solve for d: a=b2x√d/c - f    (a equals bsquared times square root of d, divided by c minus f)

 

Solve for d:
a = (b^2 sqrt(d) x)/c-f

a = (b^2 sqrt(d) x)/c-f is equivalent to (b^2 sqrt(d) x)/c-f = a:
(b^2 sqrt(d) x)/c-f = a

Rewrite the left hand side by combining fractions. (b^2 sqrt(d) x)/c-f  =  (b^2 sqrt(d) x-c f)/c:
(b^2 sqrt(d) x-c f)/c = a

Multiply both sides by c:
b^2 sqrt(d) x-c f = a c

Add c f to both sides:
b^2 sqrt(d) x = a c+c f

Divide both sides by b^2 x:
sqrt(d) = (a c)/(b^2 x)+(c f)/(b^2 x)

Raise both sides to the power of two:
Answer: | d = ((a c) / (b^2 x)+(c f) / (b^2 x))^2

 Jan 26, 2016

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