A spherical soap bubble lands on a horizontal wet surface and forms a hemisphere of the same volume. Given the radius of the hemisphere is 3 cm, find the radius of the original bubble.
Because of the area ratio of 3d shapes. You have to multiply by cube rt (ratio) so the radius is 3*cubert2
If the half bubble were a whole bubble the volume would be double.
so
\(r^3\;\;\alpha\;\; R^3\\ R^3=2r^3\\ 3^3=2r^3\\ 27=2r^3\\ \sqrt[3]{\frac{27}{2}}=r\\ r=\sqrt[3]{\frac{27}{2}} \)