+0  
 
+3
491
27
avatar+91469 

Here is a question just for LaTex beginners (Like DragonSlayer)

Write 3/5 as an upright fraction using Latex.

you have to open up the LaTex tab and write it in there.

You can refer to the LaTex Sticky topic to try and work out how

OR you can look back over old answers

OR you can google it.     :)

DS, If you can manage this all by yourself I will give you thumbs up!    

Melody  Jul 30, 2014

Best Answer 

 #19
avatar+3450 
+8

Had to look up a few things, but here it is!

$$\Big(\overline{x} \pm z\frac{s}{\sqrt{n}}\Big)$$

Or, alternatively:

$$\left(\overline{x} \pm z\frac{s}{\sqrt{n}}\right)$$

NinjaDevo  Jul 31, 2014
Sort: 

27+0 Answers

 #1
avatar+81029 
+8

$$\frac{3}{5}$$

Who says an old dog can't learn new tricks????

Where's my points ??.......Where's my points ??.....Where's my points ??..........Where's my points ??..........Where's my points ??.........

 

 

CPhill  Jul 30, 2014
 #2
avatar+4471 
+8

$$\frac{3}{5}$$ 

AzizHusain  Jul 30, 2014
 #3
avatar+91469 
+3

Ok you two - fair enough.

Dragon was complaining that if he only answered validly then there would be nothing there for him at all.

BUT I want you two to learn as well.  

Something harder.

okay see if you can write the quadratic formula in LaTex. All set out beautifully.

-------------------------------------------------------

THIS NEXT ONE IS JUST FOR DRAGON!    Write 6 and three quarters in LaTex (as a whole number and an upright fraction).

--------------------------------------------------------

Melody  Jul 31, 2014
 #4
avatar+81029 
+3

Aw, heck....!!! You mean Aziz and I can't play, too???

I'm taking my marbles and going home........

 

CPhill  Jul 31, 2014
 #5
avatar+91469 
0

YES I WANT YOU TO PLAY TOO!  CAN'T YOU DO THE HARD ONE!

ARN'T YOU UP FOR A CHALLENGE?

YESTERDAY I TOLD YOU YOUR BLOOD WAS WORTH BOTTLING AN NOW YOU ARE PIKING!!!

COME ON - GIVE IT A GO!

Melody  Jul 31, 2014
 #6
avatar+81029 
+5

$$\begin{array}{*{20}c} {x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} & {{\rm{when}}} & {ax^2 + bx + c = 0} \\ \end{array}$$

What a genius I am....!!!!   You know....this copying and pasting code stuff is pretty brain-draining ....!!!!

 

CPhill  Jul 31, 2014
 #7
avatar+91469 
0

EXCELLENT CHRIS - I KNEW YOU COULD DO IT!!!!

It gets much easier with practice.

Here is a very special gift just of you!  I hope that you don't already have one like this - It is rare!

 

Do you want to play again?

Melody  Jul 31, 2014
 #8
avatar+81029 
0

WOW...that's a pretty cool image!!!...I might even consider that as a new avatar - it's time to change mine, anyway......thanx......

 

 

CPhill  Jul 31, 2014
 #9
avatar+91469 
0

That would make a great avatar for you!  Although I really like the one that you have now.  It is so you!

Melody  Jul 31, 2014
 #10
avatar+91469 
+3

CHRIS CHEATED (NOT REALLY)  - I DIDN'T SPELL OUT THE RULES PROPERLY DID I CHRIS

You can keep your points and your marble.  So please stay and play  

Chris can you please copy that code and paste it straight onto the post underneath the output.

Then I will talk you through it - It is more complicated then it needed to be. 

Melody  Jul 31, 2014
 #11
avatar+3450 
+8

Let me try.

$$\frac{3}{5}$$

$$x= \frac{-b\pm\sqrt{b^2-4ac}}{2a}$$

 

:D

NinjaDevo  Jul 31, 2014
 #12
avatar+91469 
+3

That is great Ninja.  That is all you needed to do Chris.

Chris got his from the site entitled. "How to get from Minesota to Louisiana via Sydney."

Although the other bit that Chris wrote was also relevant.  That is what the quadratic equation is used to solve!

Melody  Jul 31, 2014
 #13
avatar+81029 
+3

But...I'm still in Sydney !!  ....I just took the "scenic route"

 

CPhill  Jul 31, 2014
 #14
avatar+91469 
+3

Yes that is true - look at Ninja's code.  It is nice and simple.

Actually I'd still like you to display your code properly.  I'd like to take a look at it.

Thanks.    

Melody  Jul 31, 2014
 #15
avatar+81029 
0

Here's the code......

\begin{array}{*{20}c} {x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} & {{\rm{when}}} & {ax^2 + bx + c = 0} \\ \end{array}

 

CPhill  Jul 31, 2014
 #16
avatar+3450 
+3

Oh I wasn't aware that you needed that other part that Chris had.

This is fun though. Got any other challenges?

NinjaDevo  Jul 31, 2014
 #17
avatar+91469 
+3

\begin{array}{*{20}c} {x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} & {{\rm{when}}} & {ax^2 + bx + c = 0} \\ \end{array}

This is all array stuff that you do not need. It has been used as a way to separate the three parts, that is foumula, when and initial equation

the 2 backslashes before it ate only a line break so they are definitely not needed.

\begin{array}{*{20}c}    all the ampersands &  and   \end{array}

So I'm going to see what is left

 x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} & {{\rm{when} ax^2 + bx + c = 0

I don't know what the \rm{ } does.  I looks like it is meant to be short for remark but i use \mbox{  } for that

\mbox is short for message box.

If we get rid of all that then this is what I have - the output is underneath

x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{2a}}} when ax^2 + bx + c = 0

$$x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{2a}}} when ax^2 + bx + c = 0$$

Now I want a space between the three sections so I am going to use the function \qquad  (quad means 4 so I think this means leave 8 spaces. I could use \quad for a smaller gap

x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{2a}}} \qquad when\qquad  ax^2 + bx + c = 0

$$x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{2a}}} \qquad when\qquad ax^2 + bx + c = 0$$

There you go - that is looking better.

--------------------------------------------------------

Now, for my own sake I want to look at this bit

\begin{array}{*{20}c}    all the ampersands &  and   \end{array}

in particular this bit  {*{20}c}  it goes with the ampersands

It means something like  

Put the formula at the begining&use the next 20 spaces for when&centre the last bit

I am not really sure what it does and it would be really good if HEUREKA tells us.

 He know everything about LaTex.    

Melody  Jul 31, 2014
 #18
avatar+91469 
+3

Alright Ninja,

Here is another one - try reproducing this - not this big!

If you get it out then try enclosing it in big brackets

Melody  Jul 31, 2014
 #19
avatar+3450 
+8
Best Answer

Had to look up a few things, but here it is!

$$\Big(\overline{x} \pm z\frac{s}{\sqrt{n}}\Big)$$

Or, alternatively:

$$\left(\overline{x} \pm z\frac{s}{\sqrt{n}}\right)$$

NinjaDevo  Jul 31, 2014
 #20
avatar+91469 
+3

 

This is how I would have done it - it is slightly different from yours

This proves that there is more than one way to skin a cat - oh sorry kitty.

I new about using Big but it has never worked fo me when I wanted to use it!

The \left and \right is probably better most of the time because it makes it the correct size, as opposed to a fixed large size.

 

\left(\bar{x} \pm z\frac{s}{\sqrt{n}}\right)

$$\left(\bar{x} \pm z\frac{s}{\sqrt{n}}\right)$$

Here is a stack of them that you can practice on

Hint:  the flatterned s at the front of each one is an integral sign.

Melody  Jul 31, 2014
 #21
avatar+18829 
+5

 

 {*{20}c}    ?

 

Hi Melody,

I will answer your question:  the meening of {*{20}c} 

 

Generally :

*{count}{form}

Example:

{*{20}c}   means  {cccccccccccccccccccc}    "c" twenty times

{*{3}{|r}}  means  {|r|r|r}                        "|r" three times

heureka  Jul 31, 2014
 #22
avatar+91469 
0

OK Thanks Heureka   

Melody  Jul 31, 2014
 #23
avatar+8256 
0

Melody, can I try?

DragonSlayer554  Jul 31, 2014
 #24
avatar+91469 
+3

Look here

http://web2.0calc.com/questions/here-is-a-question-just-for-latex-beginners-like-draagonslayer#r3

Never mind this was YOUR question Dragon - And I quote.

THIS NEXT ONE IS JUST FOR DRAGON!    

Write 6 and three quarters in LaTex (as a whole number and an upright fraction).

Melody  Aug 1, 2014
 #25
avatar+8256 
0

$$6\frac{3}{4}$$

I did it!!!!!

DragonSlayer554  Aug 1, 2014
 #26
avatar+8256 
0

Melody, can I do another one please?

I solved the one you told me to do.

  

DragonSlayer554  Aug 1, 2014
 #27
avatar+8256 
0

Melody, the first one is REALLY EASY.

$${\frac{{\mathtt{3}}}{{\mathtt{5}}}}$$

DragonSlayer554  Aug 1, 2014

3 Online Users

avatar
We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details