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Let $IJKLMN$ be a hexagon with side lengths $IJ = LM = 3,$ $JK = MN = 3,$ and $KL = NI = 3$.  Also, all the interior angles of the hexagon are equal.  Find the area of hexagon $IJKLMN$.

 Feb 16, 2024

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 #1
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area of a hexagon is 6 times that of each of its equalateral triangles so:
\(6\times \frac{s^2\sqrt3}{4}\\ 6\cdot9\cdot\sqrt3\div4=\boxed{\frac{27\sqrt3}{2}}\)

 Feb 16, 2024
 #1
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Best Answer

area of a hexagon is 6 times that of each of its equalateral triangles so:
\(6\times \frac{s^2\sqrt3}{4}\\ 6\cdot9\cdot\sqrt3\div4=\boxed{\frac{27\sqrt3}{2}}\)

EnormousBighead Feb 16, 2024

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