+1911 Let $IJKLMN$ be a hexagon with side lengths $IJ = LM = 3,$ $JK = MN = 3,$ and $KL = NI = 3$. Also, all the interior angles of the hexagon are equal. Find the area of hexagon $IJKLMN$.
0 area of a hexagon is 6 times that of each of its equalateral triangles so:
\(6\times \frac{s^2\sqrt3}{4}\\ 6\cdot9\cdot\sqrt3\div4=\boxed{\frac{27\sqrt3}{2}}\)
0 area of a hexagon is 6 times that of each of its equalateral triangles so:
\(6\times \frac{s^2\sqrt3}{4}\\ 6\cdot9\cdot\sqrt3\div4=\boxed{\frac{27\sqrt3}{2}}\)
