+230 Let
\[f(x) =
\begin{cases}
3x^2 + 2&\text{if } x\le 3, \\
ax - 1 &\text{if } x>3.
\end{cases}
\]
Find $a$ if the graph of $y=f(x)$ is continuous (which means the graph can be drawn without lifting your pencil from the paper).
+208 Hey there.
Might need some confirmation on this, but because it is continuous, i think that means that at x=3, the top and bottom are equal to eachother.
so: 3x^2 + 2 = ax - 1
Using this just rearrange and you can find a with x = 3
3*9+2=3*a-1
29=3a-1
30=3a
10=a
Hope this helps, im pretty sure thats how it works :)
