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Amaretta's birthday is July 27, and her brother Enzo's birthday is September 3. Every year, Amaretta and Enzo celebrate by eating cake every day from Amaretta's birthday through Enzo's birthday (including both birthdays). If they did this for the first time in 2008, how many cake-eating days will they have observed by the end of 2016?

SmartMathMan  Jan 9, 2018

Best Answer 

 #1
avatar+7336 
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They eat cake on July 27, July 28, July 29, July 30, and July 31.  That is  5  days.

They eat cake every day in August.  That is  31  days.

They eat cake on Sept 1, Sept 2, and Sept 3.  That is  3  days.

 

the number of cake-eating days per year   =   5 + 31 + 3   =   39

 

They do this in the years  '08 , '09 , '10 , '11 , '12 , '13 , '14 , '15 , and  '16 .  That is  9  years.

 

39 cake-eating days per year  *  9 years   =   351 cake-eating days

hectictar  Jan 9, 2018
 #1
avatar+7336 
+1
Best Answer

They eat cake on July 27, July 28, July 29, July 30, and July 31.  That is  5  days.

They eat cake every day in August.  That is  31  days.

They eat cake on Sept 1, Sept 2, and Sept 3.  That is  3  days.

 

the number of cake-eating days per year   =   5 + 31 + 3   =   39

 

They do this in the years  '08 , '09 , '10 , '11 , '12 , '13 , '14 , '15 , and  '16 .  That is  9  years.

 

39 cake-eating days per year  *  9 years   =   351 cake-eating days

hectictar  Jan 9, 2018

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