Hey, I have a maths research assignment(grade 9) and I was wondering how I can find the first three terms of a geometric progression, knowing that r=3, term2= 9 & term12=531441 Thanks
If the first term is "a" then the n'th term is a*rn-1 so you have:
From term 2: a*3 = 9 so a = 3; and this gives the 12th term as 3*311 = 531441.
You now have the first and second terms. I'll leave you to work out the third term.