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hey i need some help i am trying to do $$\left({\frac{{\mathtt{5}}{\mathtt{\,\times\,}}{{\mathtt{e}}}^{\left({\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}}{\left({\mathtt{10}}{\mathtt{\,\times\,}}{{\mathtt{e}}}^{{\mathtt{x}}}\right)}}\right)$$ and similar problems to this but i cant figure it out and i cant find it anywhere in my book

 Jan 29, 2015

Best Answer 

 #2
avatar+95369 
+5

We can do a little more with this anon

$$\\\frac{5e^{4x}}{10e^x}\\\\
=\frac{e^{4x}}{2e^x}\\\\
=\frac{e^{4x-x}}{2}\\\\
=\frac{e^{3x}}{2}\\\\$$

.
 Jan 30, 2015
 #1
avatar
+5

$${\frac{\left({\mathtt{5}}{\mathtt{\,\times\,}}{{\mathtt{e}}}^{\left({\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}\right)}{\left({\mathtt{10}}{\mathtt{\,\times\,}}{{\mathtt{e}}}^{{\mathtt{x}}}\right)}}$$

$${\frac{{\mathtt{5}}}{{\mathtt{10}}}}$$ * $${\frac{{{\mathtt{e}}}^{\left({\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}}{{{\mathtt{e}}}^{{\mathtt{x}}}}}$$

.
 Jan 30, 2015
 #2
avatar+95369 
+5
Best Answer

We can do a little more with this anon

$$\\\frac{5e^{4x}}{10e^x}\\\\
=\frac{e^{4x}}{2e^x}\\\\
=\frac{e^{4x-x}}{2}\\\\
=\frac{e^{3x}}{2}\\\\$$

Melody Jan 30, 2015

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