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Hey! Was wondering if you knew how to subtract 2(56^1/2) - 5(20^1\2)?

 

I'm having issues remembering how to sovle for those, currently working on Mean Value Theorem and with g(x)= (x(x-1))^1\2)/x-3 with three intervals, (-1,2), (2,5), and (5,8). Only one of the intervals work, (5,8) since its the only interval that has a continuous line. I then inputted the intervals as x into the first equations and got these answers:

 

a=5

b=8

 

g(5)= (20^1\2)/2

g(8)= (56^1\2)/5

 

So I inputted those into the Mean Value Theorum and got this equation:

 

(((56^1/2)/5)-((20^1\2)/2)/10)/3

 

Just trying to figure out how to solve this equation and then I think I'm good! Thank you for your time!

Guest Apr 3, 2017
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 #1
avatar+77149 
+1

2 √56  - 5 √20  =

 

2 √[ 4 * 14 ]  - 5  √ [4 * 5 ]  =

 

2 * √4 * √ 14   -  5 * √4  *  √ 5   =

 

2 * 2 *  √ 14   -   5 * 2 *  √ 5  =

 

4 √14  -  10 √5

 

 

cool cool cool

CPhill  Apr 3, 2017

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