What is the ratio of the smaller circle's area to the larger circle's area?
Give your answer in fully simplified form. It should look like "x:y", where x and y are replaced by integers.
[asy]
size(4cm);
pair o=(0,0); pair x=(0.9,-0.4);
draw(Circle(o,sqrt(0.97)));
draw(Circle((o+x)/2,sqrt(0.97)/2));
dot(o); dot(x); dot(-x);
draw(-x--x);
[/asy]
+934 This is some sort of assembly script not laTex. I realize that I thought this was laTex the last time you posted this question. You'll have to wait for someone who knows how to use this script to solve this problem for you.
Hope it helps!
+4622 The diagram should look like this:
Let the smaller circle have radius of length y units and that means that the bigger circle has a radius of length 2y units.
Thus, the smaller circle's area is \(\pi(y)^2\) and the larger circle's area is \(\pi(2y)^2=\pi4y^2\) units.
Thus, the answer is 1:4.
