+0  
 
0
40
4
avatar+78 

Hi again Forum!

I am struggling on this problem as of right now and would like some pointers.
 

Recall that a Mobius transformation has an equation of the form f(z) = az+b/cz+d, where a, b, c, and d are complex numbers.

Suppose that f(z) is a Mobius transformation such that f(1) = i, f(-1) = 1, and f(i) = -1. Find the value of f(-i).

 

I have tried multiplying different combinations of the functions to try to get the same base equation as f(-i). It hasn't worked, so maybe I am looking at this problem from the wrong angle. Thanks again everyone for helping students like us!

 

BasicMaths

 Feb 7, 2020
 #1
avatar
0

Didn't we have this question just a little while ago ?

And wasn't it answered back then ?

 Feb 7, 2020
 #2
avatar+78 
+1

Nope, I checked. Or maybe I just didn't look that far back! 😂

 Feb 7, 2020
 #3
avatar
0

We did, Jan 26th. I made a note of it.

Guest Feb 7, 2020
 #4
avatar+78 
0

Huh, thanks Guest, I will check it out. :)

 Feb 7, 2020

31 Online Users

avatar
avatar
avatar