Hi again Forum!
I am struggling on this problem as of right now and would like some pointers.
Recall that a Mobius transformation f has an equation of the form f(z) = az+b/cz+d, where a, b, c, and d are complex numbers.
Suppose that f(z) is a Mobius transformation such that f(1) = i, f(-1) = 1, and f(i) = -1. Find the value of f(-i).
I have tried multiplying different combinations of the functions to try to get the same base equation as f(-i). It hasn't worked, so maybe I am looking at this problem from the wrong angle. Thanks again everyone for helping students like us!
Didn't we have this question just a little while ago ?
And wasn't it answered back then ?
Nope, I checked. Or maybe I just didn't look that far back! 😂