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avatar+1821 

$$Consider the polynomial
$$
f(t) = t^3 + 6t^2 + 12t + 8.
$$
What are the coefficients of $f(t-1)$? Enter your answer as an ordered list of four numbers. For example, if your answer were $f(t-1) = t^3 + 3t^2 - 2t + 7$, you'd enter (1,3,-2,7). (This is not the actual answer.)$$

 Apr 26, 2015
 #1
avatar+118139 
0

Hi Mellie, 

First you have to replace all the ts with (t-1)

 

$$\\f(t) = t^3 + 6t^2 + 12t + 8\\
f(t-1)=(t-1)^3+6(t-1)^2+12(t-1)+8\\$$

 

Now you have to expand it - do you know how to do that?

 Apr 26, 2015

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