Hi evry1! Been a while. Gr8 2 c yal though.

thx solveit.

 

but i dn't get how u got the '168' 4 ques 1. (b)

n i need help 4 ques 3. (d) and (e)

 

can u help plz.

and thx again

1. In a quadrilateral PQRS, the angles P, Q and R are in the ratio 1:4:8 and their sum is 273degrees.

    Find (a) angle S (b) angle R

(a) 360-273= 87degrees

     angle S= 87degrees

 

So you found angle S right ! :)

 

angle R:

the angles P, Q and R are in the ratio 1:4:8 and their sum is 273degrees.

you can write in term s of 1:4:8    1x:4x:8x   and their sum is 273degrees:

\(x+4x+8x=273 \\ 13x=273 \\ x=21\)

 

our

R=8x

R=168

 

2.A sum of money is divided in the ratio 2:3:7. Given that the largest share is $112, calculate the smallest share

 

So the largest is 7x which is 112:

\(7x=112 \\ x=16 \)

 

and the smallest one is 2x :

\(x=16 \\ 2x=32\)

 

3. Express the following ratio in their lowest forms, giving your answer in the form m:n where m and n are integers.

(a) 42:30

\(42:30 \text{ (devide both sides by 2 )}\\ \frac{42}{(2)}:\frac{30}{(2)} \\ 21:15 \text{ (devide both sides by 3 )}\\ \frac{21}{(3)}:\frac{15}{(3)}\\ 7:5\)

 

for that you need to find common devisor and devide it until you will not left with any common devisor (sorry for english :D).The others in the same rule (if you will stuck write it on the calculator here it will show you it on the fraction form for example:\(\frac12 \)  it is 1:2)

Hi Eloise and Solveit,  

Thanks for all those answers Solveit. :)

I have only just seen your post.  Do you understand now Eloise?  If not then say so!

And, it is great to see you one the forum again too Eloise :)