+1124 Hi good people,
I did try this sum, but it becomes terribly horrible at some stage, and I just gave up...it says to calculate x and y if:
\(x+yi={3+2i \over 4-3i}\)
I rasionalised the denominator and carried on, but like I said, the sum just gets to much, and I fell out of the bus...please help!!..thanx again..
+6251 I hope you weren't too badly injured.
\(\dfrac{3+2i}{4-3i} = \\~\\ \dfrac{3+2i}{4-3i}\cdot \dfrac{4+3i}{4+3i} \\~\\ \dfrac{(12-6)+i(8+9)}{25}= \dfrac{6+17i}{25}\\~\\ \dfrac{6}{25}+\dfrac{17}{25}i\)
+1124 haha, Hi Rom,
thanx for the sum, uhm, I do understand the part you did, what I fail to understand is that they ask to solve x and then y?
+1124 huh???...golly me!!!...that's it???....Melody, ..thank you...hahahaha...yep, i certainly have a looong way to go...
+1124 OOOHHHH!!!!!!... now I see it!!!!!!!!!!!...never!!!!!...I always tend to look too deep into things.....man!!!!
