Hi good people,

I did try this sum, but it becomes terribly horrible at some stage, and I just gave up...it says to calculate x and y if:

\(x+yi={3+2i \over 4-3i}\)

I rasionalised the denominator and carried on, but like I said, the sum just gets to much, and I fell out of the bus...please help!!..thanx again..

juriemagic May 20, 2019

#1**+3 **

I hope you weren't too badly injured.

\(\dfrac{3+2i}{4-3i} = \\~\\ \dfrac{3+2i}{4-3i}\cdot \dfrac{4+3i}{4+3i} \\~\\ \dfrac{(12-6)+i(8+9)}{25}= \dfrac{6+17i}{25}\\~\\ \dfrac{6}{25}+\dfrac{17}{25}i\)

.Rom May 20, 2019

#2**+2 **

haha, Hi Rom,

thanx for the sum, uhm, I do understand the part you did, what I fail to understand is that they ask to solve x and then y?

juriemagic
May 20, 2019

#4**+1 **

huh???...golly me!!!...that's it???....Melody, ..thank you...hahahaha...yep, i certainly have a looong way to go...

juriemagic
May 20, 2019

#5**+1 **

OOOHHHH!!!!!!... now I see it!!!!!!!!!!!...never!!!!!...I always tend to look too deep into things.....man!!!!

juriemagic
May 20, 2019