Hi! How do you simplify (4x^6y^5)^2? Im doing a summer course in math

$$(4x^6y^5)^2$$

There are rules for this but it is probably better if you just understand so I will try to explain.

$$(4x^6y^5)^2\\\\ =4x^6y^5 \times 4x^6y^5\\\\ =4\times x^6 \times y^5\times 4\times x^6 \times y^5\\\\ =4\times 4\times x^6 \times x^6\times y^5\times y^5 \\\\ =16x^{12} y^{10} \\\\ \mbox{Now for the short cut method}\\ (4 x^6y^5)^2 = 4^2x^{6*2}y^{5*2} = 16x^{12}y^{10}$$

If you do not understand then please make another post on THIS thread.  Thank you.

Thanks a lot! I will take a look :)

Edit: I understand perfectly now!

This is a very different question.

It is:

(((4x-)^6y)^5)^2)

=((4x)^6y)^10

=(4x)^60y

This is the answer for ur question

(((4x-)^6y)^5)^2)

Puttin a minus sign there does not make sense Sasini.