+0  
 
+3
48
5
avatar+161 

If a coin is flipped 4 times, how many distinct sequences of heads and tails occur?

 

 

 

This is part of my homework, and I would like a solution. Thanks.

 Jul 9, 2020
edited by tigernathan  Jul 9, 2020
 #1
avatar+252 
+3

There are two possibilities for each flip (Heads or Tails). You multiply those together to get the total number of unique sequences.

 

Here’s an example for 2 flips: HH - HT - TT - TH. (That’s 2*2, or 2^2)

 

You want to know how many distinct sequences of heads and tails occur if a coin is flipped 4 times. 

That would be 2^4 so 16.

 

When you toss a coin once, there are two possible outcomes: heads and tails. Tossing a coin four times, on the face of it, appears to yield 2x2x2x2 outcomes, or in other words, sixteen.

 

 

I hope that was corect and helpful, also sorry it took me a while.

 

cheekyblushsmiley

 Jul 9, 2020
edited by MathWizPro  Jul 9, 2020
edited by MathWizPro  Jul 9, 2020
edited by MathWizPro  Jul 9, 2020
edited by MathWizPro  Jul 9, 2020
 #2
avatar+161 
+3

Take your time

 Jul 9, 2020
edited by tigernathan  Jul 9, 2020
 #3
avatar+161 
+3

I have a question:

I have tried solving this question and got 16. I just tried solving it and I think it's 16 because 2^4. One is tails, and the other is heads. So, 2. Since it is 4 times, I think 2^4. Is this correct?

 

Whoops. You just solved it.

 Jul 9, 2020
edited by tigernathan  Jul 9, 2020
 #4
avatar+252 
+3

Lol, yes I'm pretty sure that's correct... See! You didn't even need much help, very smart cheekylaugh Good job!

MathWizPro  Jul 9, 2020
 #5
avatar+161 
+3

xD I was a little confused.

tigernathan  Jul 9, 2020

21 Online Users

avatar