If a coin is flipped 4 times, how many distinct sequences of heads and tails occur?

This is part of my homework, and I would like a solution. Thanks.

tigernathan Jul 9, 2020

#1**+3 **

There are two possibilities for each flip (Heads or Tails). You multiply those together to get the total number of unique sequences.

Here’s an example for 2 flips: HH - HT - TT - TH. (That’s 2*2, or 2^2)

You want to know how many distinct sequences of heads and tails occur if a coin is flipped 4 times.

That would be 2^4 so **16**.

When you toss a coin once, there are two possible outcomes: heads and tails. Tossing a coin four times, on the face of it, appears to yield 2x2x2x2 outcomes, or in other words, sixteen.

I hope that was corect and helpful, also sorry it took me a while.

MathWizPro Jul 9, 2020

edited by
MathWizPro
Jul 9, 2020

edited by MathWizPro Jul 9, 2020

edited by MathWizPro Jul 9, 2020

edited by MathWizPro Jul 9, 2020

edited by MathWizPro Jul 9, 2020

edited by MathWizPro Jul 9, 2020

edited by MathWizPro Jul 9, 2020

#3**+3 **

I have a question:

I have tried solving this question and got 16. I just tried solving it and I think it's 16 because 2^4. One is tails, and the other is heads. So, 2. Since it is 4 times, I think 2^4. Is this correct?

Whoops. You just solved it.

tigernathan Jul 9, 2020

#4**+3 **

Lol, yes I'm pretty sure that's correct... See! You didn't even need much help, very smart Good job!

MathWizPro
Jul 9, 2020