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Given that y is inversely proportional to x² and x is always positive. If y=27 when x = 6, calculate the value of x when y=3
 Sep 21, 2017
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Given that y is inversely proportional to x² and x is always positive. If y=27 when x = 6, calculate the value of x when y=3

 

\(y\;\alpha \; \frac{1}{x^2} \qquad x>0\\ y\;= \; \frac{k}{x^2} \\ 27= \; \frac{k}{36} \\ k=27*36\\ k= 972\\ y=\frac{972}{x^2}\\~\\ when \;y=3\\ 3=\frac{972}{x^2}\\ 3x^2=972\\ x^2=324\\ x=18 \)

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 Sep 21, 2017

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