+0  
 
0
241
1
avatar
Given that y is inversely proportional to x² and x is always positive. If y=27 when x = 6, calculate the value of x when y=3
Guest Sep 21, 2017
 #1
avatar+93880 
+1

Given that y is inversely proportional to x² and x is always positive. If y=27 when x = 6, calculate the value of x when y=3

 

\(y\;\alpha \; \frac{1}{x^2} \qquad x>0\\ y\;= \; \frac{k}{x^2} \\ 27= \; \frac{k}{36} \\ k=27*36\\ k= 972\\ y=\frac{972}{x^2}\\~\\ when \;y=3\\ 3=\frac{972}{x^2}\\ 3x^2=972\\ x^2=324\\ x=18 \)

Melody  Sep 21, 2017

7 Online Users

avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.