state the phase shift for y = sin(x - 2π) and graph it ???
also state the phase shift and graph y = 2cos(x/4 + π/2) ?
Thank you so much :)
(**in case the π symbol doesn’t come out, its pi!!)
y = sin ( x - 2pi)
This the sine graph shifted to the right by 2pi rads......however.....since the normal peiod is 2pi, it will not appear different from the normal sine graph
Here's the graph : https://www.desmos.com/calculator/z4edgadelv
y = 2cos (x/4 + pi/2)
Write this as :
y = 2cos(1/4) (x - 2pi)
This is the normal cosine graph with a period 4 times as long as normal, vertically stretched by a factor of 2 and with a phase shift of 2pi rads to the right
Here's the parent graph and this one on the same axis