+0

+1
199
1
+732

Perhaps the most common error in ranking poker hands involves confusing the order of a straight and a flush.

A straight is 5 cards with consecutive rank, like 45678. The cards rank A,2,3,4,5,6,7,8,9,10,J,Q,K,A. Note that an ace ("A") can be used as high (as in 10JQKA) or as low (as in A2345), but it can't be used as both high and low in the same hand. (That is, you can't use an ace to loop around. KA234 does not count as a straight.)

A flush is 5 cards of the same suit.

If 5 cards are drawn from the deck at random (without replacement) to form a hand, which hand is more likely: a straight or a flush?

I know that to calculate flush its:

$$4 \cdot {13 \choose 5} =5148$$

But I'm not sure how to calculate the straights.

I know the answer is straight since I've played poker before (with my family), but I don't know how to calculate it..

thanks

:)

May 2, 2020
edited by lokiisnotdead  May 2, 2020

#1
+652
0

Is this the same question?

https://web2.0calc.com/questions/perhaps-the-most-common-error-in-ranking-poker-hands-involves-confusing-the-order-of-a-straight-and-a-flush-a-straight-is-5-cards-with-cons

May 2, 2020