+142 In right triangle PQR, we have angleQ=angleR and PR=6\sqrt(2). What is the area of triangle PQR?
+142 \(36\).
\(6\sqrt2^2\)
Square root of \(2\) squared\(=2\)
\(6^2=36\)
\(36\cdot2\)\(=72 \)
So \(6\sqrt2^2=72\)
Area of triangle\(=(l1\cdot{l2})\div2=a\)
We already calculated the parentheses so now we divide by \(2\)
\(72\div2=36\)
Area of\(\triangle{PQR}=36\)
π
I figured it out :D
