In right triangle PQR, we have angleQ=angleR and PR=6\sqrt(2). What is the area of triangle PQR?
6sqrt 2 ^2 / 2 = 36, by 45-45-90 triangles
yes that works
36.
6√22
Square root of 2 squared=2
62=36
36⋅2=72
So 6√22=72
Area of triangle=(l1⋅l2)÷2=a
We already calculated the parentheses so now we divide by 2
72÷2=36
Area of△PQR=36
π
I figured it out :D