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A chess tournament is being held with 100 participants. Here are the home cities of the 100 participants: $\bullet$ 62 live in New York City (New York) $\bullet$ 17 live in Los Angeles (California) $\bullet$ 11 live in Dallas (Texas) $\bullet$ 6 live in Seattle (Washington) $\bullet$ 3 live in Little Rock (Arkansas) $\bullet$ 1 lives in Pocatello (Idaho) To save on transportation costs, the organizers of the tournament want to minimize the total distance that the participants must travel. (For simplicity, assume that distance is measured by the crow flies.) Mrs. Wiggins argues that since most of the participants live in New York City, the total distance would be minimized if the tournament was held there. But Mr. Tudball argues that since the participants are spread out throughout the country, the total distance would be minimized if the tournament was held in a more central location, like Hutchinson, Kansas. Who is correct?

 Aug 27, 2020
 #1
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I ran a regression analysis on your data, and the optimal location is Kansas City, Missouri, for a total distance of 28,762 miles.

 Aug 27, 2020
 #2
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Hi! i hear your paper is due tomorrow. im sorry but can you learn your topic, instead of giving your homework to us or whatever this is. i trust its much more effective! laugh

Guest Aug 27, 2020

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