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0
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avatar+2496 

body p

 Jan 18, 2016

Best Answer 

 #1
avatar+95865 
+15

Note, Solveit.......the sum of the interior angles of any quadrilateral  = 360°

 

So .....angles A + B + C + D  = 360°    (1)

 

A =  2 times angle B →   B  = A/2

A =  4 times angle C →   C  = A/4

A =8 times angle D →   D = A/8

 

So....substituting into (1)

 

A + A/2 + A/4 + A/8  = 360°   get a common denominator

 

[8A + 4A + 2A + A] / 8 = 360°       simplify the left side

 

15A / 8 =   360°      multiply both sides by 8

 

15A  =  2880°     divide both sides by 15

 

A = 192°

 

So....D  = A/8  = 192° / 8     =   24°    (E)

 

 

 

cool cool cool

 Jan 18, 2016
 #1
avatar+95865 
+15
Best Answer

Note, Solveit.......the sum of the interior angles of any quadrilateral  = 360°

 

So .....angles A + B + C + D  = 360°    (1)

 

A =  2 times angle B →   B  = A/2

A =  4 times angle C →   C  = A/4

A =8 times angle D →   D = A/8

 

So....substituting into (1)

 

A + A/2 + A/4 + A/8  = 360°   get a common denominator

 

[8A + 4A + 2A + A] / 8 = 360°       simplify the left side

 

15A / 8 =   360°      multiply both sides by 8

 

15A  =  2880°     divide both sides by 15

 

A = 192°

 

So....D  = A/8  = 192° / 8     =   24°    (E)

 

 

 

cool cool cool

CPhill Jan 18, 2016
 #2
avatar+2496 
+5

aaaa thanks CPhill ! :)

 Jan 18, 2016

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