+0  
 
+1
128
3
avatar+578 

I don't understand how to find a sigma equation from a set of numbers.

 

 

-5+2+9+16+...+261+268

 

 

How do I get a sigma equation from this?

OfficialBubbleTanks  Feb 23, 2018
 #1
avatar+578 
0

Oh wait, nobody is online. LOVELY! >:(

OfficialBubbleTanks  Feb 23, 2018
 #2
avatar+12725 
+2

\(\sum_{1}^{40}\) 7n-12

ElectricPavlov  Feb 23, 2018
 #3
avatar+93305 
+1

 

My answer is the same as EP's

EP you might like to look at my Latex here too :)

 

 

 

-5+2+9+16+...+261+268

This is the sum of an AP

a=-5, d=7,   

 

\(T_n=a+(n-1)d\\ T_n=-5+(n-1)*7\\ T_n=-5+7n-7\\ T_n=7n-12\\ Find\;n\;when\;T_n=268\\ 268=7n-12\\ 280=7n\\ n=40 \)

 

\(\displaystyle\sum_{n=1}^{40}\;7n-12 \\\)

---------------------

 

LATEX COMMAND

\displaystyle\sum_{n=1}^{40}\;7n-12 

Melody  Feb 24, 2018

29 Online Users

avatar
avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.