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Find the number of possible choices for a 4-digit PIN if the digits cannot be repeated.

Can anyone help? Thanks.

Llama on!

MamaLlama

 Apr 7, 2015

Best Answer 

 #1
avatar+130466 
+10

Assuming that 0 could be used in any position, we have 10 choices for the first digit,  nine for the second, eight for the third and seven for the fourth.

So....

10 x 9 x 8 x 7 = 70 x 72  = 5040 possible PINs

 

  

 Apr 7, 2015
 #1
avatar+130466 
+10
Best Answer

Assuming that 0 could be used in any position, we have 10 choices for the first digit,  nine for the second, eight for the third and seven for the fourth.

So....

10 x 9 x 8 x 7 = 70 x 72  = 5040 possible PINs

 

  

CPhill Apr 7, 2015

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