How can i find the end behavior with these two functions?
\(f(x)=\frac{-6x}{3x-5}\\ f(x)=x^2-4x-5\)
\(\frac{-6x}{3x-5}=x^2-4x-5 \)
\(-6x=(x^2-4x-5)\times (3x-5)\\ -6x=3x^3-5x^2-12x^2+20x-15x+25\\ \color{blue}3x^3-17x^2+11x+25=0\)
\(x_1 \approx-.88231\\ x_2\approx 2.1443\\ x_3 \approx 4.4041\\ WOLFRAM\ |\ ALPHA\)
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Mmm I do not think that is what the guest wanted asinus :)
\(f(x)=\frac{-6x}{3x-5}\)
This has an asymptote at
3x-5=0
x=5/3
lim as x tends to 5/3 from above = - infinity
lim as x tends to 5/3 from below = + infinity
As x tends to +infinity y tends to -2
As x tends to -infinity y tends to -2
Here is the graph.