+0

# How can I write an exponential function whose graph passes through the points (0, -6) and (-2,-54)?

0
959
1

How can I write an exponential function whose graph passes through the points (0, -6) and (-2,-54)?

Guest Mar 5, 2015

#1
+17721
+5

You are looking for an equation of this form:  y  =  a·bx

Using the point (0, -6)   --->   -6  =  a·b0   --->   -6  =  a·1   --->   -6  =  a

So, now the equation is:  y  =  -6·b

Now, use the point (-2, -54)   --->   -54  =  -6b-2   --->   9  =  b-2   --->   1/9  =  b2   --->   b  =  ±(1/3)

So:  either:  y  =  -6·(1/3)x   or   y  =  -6·(-1/3)x

geno3141  Mar 6, 2015
Sort:

#1
+17721
+5

You are looking for an equation of this form:  y  =  a·bx

Using the point (0, -6)   --->   -6  =  a·b0   --->   -6  =  a·1   --->   -6  =  a

So, now the equation is:  y  =  -6·b

Now, use the point (-2, -54)   --->   -54  =  -6b-2   --->   9  =  b-2   --->   1/9  =  b2   --->   b  =  ±(1/3)

So:  either:  y  =  -6·(1/3)x   or   y  =  -6·(-1/3)x

geno3141  Mar 6, 2015

### 11 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details