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How can I write an exponential function whose graph passes through the points (0, -6) and (-2,-54)?

Guest Mar 5, 2015

Best Answer 

 #1
avatar+17721 
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You are looking for an equation of this form:  y  =  a·bx

Using the point (0, -6)   --->   -6  =  a·b0   --->   -6  =  a·1   --->   -6  =  a

So, now the equation is:  y  =  -6·b

Now, use the point (-2, -54)   --->   -54  =  -6b-2   --->   9  =  b-2   --->   1/9  =  b2   --->   b  =  ±(1/3)

So:  either:  y  =  -6·(1/3)x   or   y  =  -6·(-1/3)x

geno3141  Mar 6, 2015
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1+0 Answers

 #1
avatar+17721 
+5
Best Answer

You are looking for an equation of this form:  y  =  a·bx

Using the point (0, -6)   --->   -6  =  a·b0   --->   -6  =  a·1   --->   -6  =  a

So, now the equation is:  y  =  -6·b

Now, use the point (-2, -54)   --->   -54  =  -6b-2   --->   9  =  b-2   --->   1/9  =  b2   --->   b  =  ±(1/3)

So:  either:  y  =  -6·(1/3)x   or   y  =  -6·(-1/3)x

geno3141  Mar 6, 2015

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