How can I write an exponential function whose graph passes through the points (0, -6) and (-2,-54)?
You are looking for an equation of this form: y = a·bx
Using the point (0, -6) ---> -6 = a·b0 ---> -6 = a·1 ---> -6 = a
So, now the equation is: y = -6·bx
Now, use the point (-2, -54) ---> -54 = -6b-2 ---> 9 = b-2 ---> 1/9 = b2 ---> b = ±(1/3)
So: either: y = -6·(1/3)x or y = -6·(-1/3)x
You are looking for an equation of this form: y = a·bx
Using the point (0, -6) ---> -6 = a·b0 ---> -6 = a·1 ---> -6 = a
So, now the equation is: y = -6·bx
Now, use the point (-2, -54) ---> -54 = -6b-2 ---> 9 = b-2 ---> 1/9 = b2 ---> b = ±(1/3)
So: either: y = -6·(1/3)x or y = -6·(-1/3)x