+0

# How do I find the altitude of a orthodiagonal right trapezoid?

+1
354
4
+80

What is the formula?

Also, can you prove it?

Jan 15, 2019

#1
+533
0

well i saw this written by another guy, its sum of two bases over 2..

maybe use similar triangles to prove? IDK!

Jan 15, 2019
#2
+57
+1

Before reading this answer, you might want to take a look at

https://web2.0calc.com/questions/geometry-trapezoid

An orthodiagonal right trapezoid essentially means a trapezoid in where the diagonals intersect at a right angle.

Will do an answer when I can get a camera to work.

Jan 15, 2019
#3
+80
0

Thank you

Pls asap though

itsyaboi  Jan 15, 2019
#4
+57
+1

I was unable to get a camera to work, so You'll have to read carfully.

1.Construct a trapezoid with the description of the problem.

2.Name the verticies starting from the top left side, going clockwise, A,B,C and D respectively.

3.Draw altitudes going down from A and B. Name the points where they intersect DC F and E, F is on the left.

4.Let side $$\overline{AB}$$ be a, and $$\overline{DC}$$ be b. $$\overline{FE}$$ is a, and $$\overline{EC}$$ = $$\overline{DF}$$ = $$\frac{b-a}{2}$$.

5.Let the intersection of diagonals be O.

6.$$\triangle DOC$$ is a 45-45-90 triangle.

See if you can work it out from there.

Jan 15, 2019