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How do I find the intercepts of -x-y=2

 Dec 19, 2014

Best Answer 

 #1
avatar+1006 
+5

You need to isolate 'y' so that the equation is in y = mx + b form, or slope-intercept form.

 

-x - y = 2

-y = x + 2

y = -x - 2

 

Your y-intercept will be -2.

 

Now, to get the x-intercept, we need to isolate 'x', and then find what makes the whole equation '0'.

 

-x - y = 2

-x = y + 2

x = -y - 2

0 = -y - 2

2 = -y

-2 = y

 

So, your x-intercept will be -2.

 

Please note that it is merely coincidental that both the y-intercept and the x-intercept are the same number.

 Dec 19, 2014
 #1
avatar+1006 
+5
Best Answer

You need to isolate 'y' so that the equation is in y = mx + b form, or slope-intercept form.

 

-x - y = 2

-y = x + 2

y = -x - 2

 

Your y-intercept will be -2.

 

Now, to get the x-intercept, we need to isolate 'x', and then find what makes the whole equation '0'.

 

-x - y = 2

-x = y + 2

x = -y - 2

0 = -y - 2

2 = -y

-2 = y

 

So, your x-intercept will be -2.

 

Please note that it is merely coincidental that both the y-intercept and the x-intercept are the same number.

GoldenLeaf Dec 19, 2014

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