+0

# How do I find the series formula for a sequence that is neither arithmetic nor geometric?

0
551
1

So I have a formula,

$${\frac{{{\mathtt{100}}}^{{\mathtt{n}}}}{\left({\mathtt{50}}{\mathtt{\,\times\,}}\left({\mathtt{1}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{100}}}^{\left({\mathtt{n}}{\mathtt{\,-\,}}{\mathtt{1}}\right)}\right)\right)}} = {a}{\left({\mathtt{n}}\right)}$$

for finding the nth term of the sequence, but since It's neither arithmatic nor geometric, I don't know how to find a formula for the sum of the nth terms. Is there even a way to?

Guest May 3, 2015

#1
+26547
+5

I can't find an exact formula for the sum of N terms, but there is an approximate expression:

sum ≈ 2*N - 1.02  which gives it to two decimal places.

or sum ≈ 2*N - 1.020004 which gives it to 6 decimal places for N>3

.

Alan  May 4, 2015
Sort:

#1
+26547
+5

I can't find an exact formula for the sum of N terms, but there is an approximate expression:

sum ≈ 2*N - 1.02  which gives it to two decimal places.

or sum ≈ 2*N - 1.020004 which gives it to 6 decimal places for N>3

.

Alan  May 4, 2015

### 25 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details