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So I have a formula,

$${\frac{{{\mathtt{100}}}^{{\mathtt{n}}}}{\left({\mathtt{50}}{\mathtt{\,\times\,}}\left({\mathtt{1}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{100}}}^{\left({\mathtt{n}}{\mathtt{\,-\,}}{\mathtt{1}}\right)}\right)\right)}} = {a}{\left({\mathtt{n}}\right)}$$ 

for finding the nth term of the sequence, but since It's neither arithmatic nor geometric, I don't know how to find a formula for the sum of the nth terms. Is there even a way to?

difficulty advanced
Guest May 3, 2015

Best Answer 

 #1
avatar+27227 
+5

I can't find an exact formula for the sum of N terms, but there is an approximate expression:

 

sum ≈ 2*N - 1.02  which gives it to two decimal places.

 

or sum ≈ 2*N - 1.020004 which gives it to 6 decimal places for N>3

.

Alan  May 4, 2015
 #1
avatar+27227 
+5
Best Answer

I can't find an exact formula for the sum of N terms, but there is an approximate expression:

 

sum ≈ 2*N - 1.02  which gives it to two decimal places.

 

or sum ≈ 2*N - 1.020004 which gives it to 6 decimal places for N>3

.

Alan  May 4, 2015

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