How do I get a confidence interval of 90% from 1245(0.42)(1-0.42))=279. How do I calculate to get confidence interval?
+33657 This looks like you've supplied the variance of a binomial distribution with n = 1245 trials and probability of success, p = 0.42.
Using the Wald method (see https://en.wikipedia.org/wiki/Binomial_distribution ) the 90% confidence interval is obtained from:
p ± 1.645*√(p*(p-1)/n)
You can fill in the numbers.
.
+33657 This looks like you've supplied the variance of a binomial distribution with n = 1245 trials and probability of success, p = 0.42.
Using the Wald method (see https://en.wikipedia.org/wiki/Binomial_distribution ) the 90% confidence interval is obtained from:
p ± 1.645*√(p*(p-1)/n)
You can fill in the numbers.
.
