I have this diagram.
I know that PCQ = 45 Degrees and Angle C = 90 Degrees.
I want to prove that AB^2 + BQ^2 = PQ^2.
ugh.... I don't know what to do next.
Help would be greatly appreciated fast :D
You cannot prove it because it is not true. I assume you have written the question incorrectly.
You want to prove that AB^2 + BQ^2 = PQ^2.
But AB is bigger than PQ so the statement to be proven is not true
Sorry about that!
I meant to say AP^2 + BQ^2 = PQ^2
AC = BC = 5 | ∠ACB = 90º | ∠PCQ = 45º | ∠ACP = ∠BCQ = 22.5º
Let M be a midpoint of AB
AB = sqrt (AC2 + BC2)
PQ = 2 * [tan(PCM) * CM] ( CM = AM = BM )
AP = BQ = 1/2 (AB - PQ)
+179 
