1. Exclude the restricted values of x
\({{x^2}-x-30\over x-6}=8\)
2. Write -x as a sum
\({{x^2}-x-30\over x-6}=8,x\neq 6\)
3. Factor out x from the expression
Factor out -6 from the expression
\({{x^2}+5x-6x-30\over x-6}=8\)
4. Factor out x+5 from the expression
\({x\times (x+5)-6(x+5)\over x-6}=8\)
5. Simplify the fraction
\({x-6)\times (x+5)\over x-6}=8\)
6. Move constant to the right side and change its sign
\(x+5=8\)
7. Subtract the numbers
\(x=8-5\)
8. If any solution equals to a restricted value, exclude it
\(x=3,x\neq 6\)
9. Answer
\(x=3\)
Is this good enough?
Perfect thank you so much, sorry for the double post, just working out how the site works. Great site
No problem, I was just wondering.
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