I thought I already answered it, did I answer it wrong or something?
I thought I already answered it, did I answer it wrong or something?
Taken literally...we have
x^2-x-30/x-6 = 8
x^2 - x -30/x -14 = 0 multiply everything by x
x^3 - x^2 - 30 - 14x = 0
x^3 - x^2 - 14x - 30 = 0
By the Rational Roots Theorem, 5 is a root....and we can use synthetic division to find the remaining polynomial / roots
5 [ 1 - 1 -14 -30 ]
5 20 30
1 4 6 0
The remaining polynomial is :
x^2 + 4x + 6 ......this has no real roots......using the quad formula, the other two roots are :
-2 ± i√2
You did fine, EMP.....you answered this :
[x^2-x-30] / [ x-6] = 8 [which is what I would have assumed ].....but....
Since he/she said no brackets....I assumed the literal form of
x^2 - x -30/x - 6 = 8
Either way....they have a choice of two presentations.....LOL!!!!
Guest,
It is very rude of you to re-ask your question when it has already been answered.
You should always say thank you to the answerer and if you do not like the answer then you say why you do not like the answer.
Give the original answerer feedback and also five him/her the oportunity to fix it if there is an error or explain more if you need it.
Always remember your manners !
Thanks for your answers Chris and EightMersennePrime :))