my answer
\(y=log_bx\qquad \\ \text{Make x the subject}\\ b^y=b^{log_bx}\\ b^y=x \text{swap x and y over to find the inverse function}\\ b^x=y\\ y=b^x \)
So I have determined that the second funtion is the inverse of the first one.
So this means that they are reflections of one another across the line y=x
so draw the line y=x and reflect each ot the points across it and you will have the points for the second graph.
So
(1,0) becomes (0,1)
(2,1) becomes (1,2)
etc
my answer
\(y=log_bx\qquad \\ \text{Make x the subject}\\ b^y=b^{log_bx}\\ b^y=x \text{swap x and y over to find the inverse function}\\ b^x=y\\ y=b^x \)
So I have determined that the second funtion is the inverse of the first one.
So this means that they are reflections of one another across the line y=x
so draw the line y=x and reflect each ot the points across it and you will have the points for the second graph.
So
(1,0) becomes (0,1)
(2,1) becomes (1,2)
etc