how do i work out 5³x5x5⁴x5²=

$$n^a \times n^b=n^{a+b}$$

So $${{\mathtt{5}}}^{{\mathtt{3}}}{\mathtt{\,\times\,}}{\mathtt{5}}{\mathtt{\,\times\,}}{{\mathtt{5}}}^{{\mathtt{4}}}{\mathtt{\,\times\,}}{{\mathtt{5}}}^{{\mathtt{2}}} = {{\mathtt{5}}}^{{\mathtt{3}}}{\mathtt{\,\times\,}}{{\mathtt{5}}}^{{\mathtt{1}}}{\mathtt{\,\times\,}}{{\mathtt{5}}}^{{\mathtt{4}}}{\mathtt{\,\times\,}}{{\mathtt{5}}}^{{\mathtt{2}}} = {{\mathtt{5}}}^{\left({\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}\right)} = {{\mathtt{5}}}^{{\mathtt{10}}} = {\mathtt{9\,765\,625}}$$

$${{\mathtt{5}}}^{{\mathtt{3}}}{\mathtt{\,\times\,}}{\mathtt{5}}{\mathtt{\,\times\,}}{{\mathtt{5}}}^{{\mathtt{4}}}{\mathtt{\,\times\,}}{{\mathtt{5}}}^{{\mathtt{2}}} = {\mathtt{9\,765\,625}}$$

5^3 = 5*5*5 =125

125 * 25 =3125

3125 * (5*5*5*5) = (cant do in my head)

$${\mathtt{3\,125}}{\mathtt{\,\times\,}}{{\mathtt{5}}}^{{\mathtt{4}}} = {\mathtt{1\,953\,125}}$$

Then  1953125*5^2=

$${\mathtt{1\,953\,125}}{\mathtt{\,\times\,}}{{\mathtt{5}}}^{{\mathtt{2}}} = {\mathtt{48\,828\,125}}$$

i dont know what i done