There is, I vaguely remember, an algebraic method similar to that for calculating square roots and it's also possible to use the Newton-Raphson method, (though you would need to be good at arithmetic, hardly the sort of calculation you would attempt without a calculator).
If the number is close to some convenient cube, it's possible to make use of the binomial expansion. For example.
3√1005=(1000+5)1/3=10001/3(1+0.005)1/3=10(1+(1/3)0.005+(1/3)(−2/3)0.0052/2!+…)=10(1+0.0016667−0.0000028+…)≈10.016639
That's easily done on paper and is correct to 6dp.