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How do you construct x Route 5 given x, Euclidian style?

Guest Feb 26, 2015

Best Answer 

 #1
avatar+93289 
+5

Well I am not sure what is required but to me Euclidian geometry is anything that is constructed so perhaps this will do.

 

If you constructed a square ABCD    where the side length is 2x.

Then bisect side AB to give the point E

then join DE,  DE will be x*sqrt5 in length.

 

Here are some other ideas.  The spiral one is quite nice.

https://www.google.com.au/search?q=construct+sqrt5+euclidian+style&biw=1366&bih=629&source=lnms&tbm=isch&sa=X&ei=wvLuVOedMIrV8gXInYCgBw&ved=0CAYQ_AUoAQ#tbm=isch&q=construct+sqrt+5+euclidean+style&spell=1&imgdii=_

Melody  Feb 26, 2015
 #1
avatar+93289 
+5
Best Answer

Well I am not sure what is required but to me Euclidian geometry is anything that is constructed so perhaps this will do.

 

If you constructed a square ABCD    where the side length is 2x.

Then bisect side AB to give the point E

then join DE,  DE will be x*sqrt5 in length.

 

Here are some other ideas.  The spiral one is quite nice.

https://www.google.com.au/search?q=construct+sqrt5+euclidian+style&biw=1366&bih=629&source=lnms&tbm=isch&sa=X&ei=wvLuVOedMIrV8gXInYCgBw&ved=0CAYQ_AUoAQ#tbm=isch&q=construct+sqrt+5+euclidean+style&spell=1&imgdii=_

Melody  Feb 26, 2015

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