+129852 how do you do a(2a+3)-a(a+1) I got 3a + a squared + 1 Is that right
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You're close......let's look at it again.
Distributing the "a" across 2a + 3 in the first expression gives us 2a2 + 3a
And distributing the "-a" across a + 1 in the second expression gives us -a2 - a
So, combining like terms, we have....... a2 + 2a
(I think you might have forgotten to distribute the "-a" across the +1 in the second part.)
+1006 First, distribute the 'a's.
$$\left({\mathtt{2}}{\mathtt{\,\times\,}}{{\mathtt{a}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{a}}\right){\mathtt{\,-\,}}\left({\mathtt{2}}{\mathtt{\,\times\,}}{{\mathtt{a}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{a}}\right)$$
What will happen now is that, in order to factor the polynomials, you must set up a 3x3 grid and combine (in a similar fashion to Punnett Squares).
(I have to go now, can somebody finish this one up?)
+129852 how do you do a(2a+3)-a(a+1) I got 3a + a squared + 1 Is that right
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You're close......let's look at it again.
Distributing the "a" across 2a + 3 in the first expression gives us 2a2 + 3a
And distributing the "-a" across a + 1 in the second expression gives us -a2 - a
So, combining like terms, we have....... a2 + 2a
(I think you might have forgotten to distribute the "-a" across the +1 in the second part.)
