Thanks anon
----------------------------------------------------------------------------
I always start these with an equilateral triangle of side length 2. Angles will be 60 degrees
I then put in a height which will split the base in half.
Now you have 2 right angled triangles with hypotenuse=2 and base is 1 unit
using Pythagoras you can easily determine that the height is $${\sqrt{{\mathtt{3}}}}$$ units.
The angles in each one will be 90,60 and 30 degrees.
now you can see that sin(30) = 1/2
I draw this either on paper or in my head EVERY time.
arcsin (1/2) means
$$Sin\theta=\frac{1}{2}$$
Recall that the sin function involves the ratio of the opposite side divided by the hypotenuse. So the opposite side is half of the hypotenuse. If you draw a 30-60-90 triangle with the hypotenuse equal to 1, you can determine that the side opposite the 30 degree angle is half as long.
Thanks anon
----------------------------------------------------------------------------
I always start these with an equilateral triangle of side length 2. Angles will be 60 degrees
I then put in a height which will split the base in half.
Now you have 2 right angled triangles with hypotenuse=2 and base is 1 unit
using Pythagoras you can easily determine that the height is $${\sqrt{{\mathtt{3}}}}$$ units.
The angles in each one will be 90,60 and 30 degrees.
now you can see that sin(30) = 1/2
I draw this either on paper or in my head EVERY time.