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find 

lim [ g(x) - f(x)

x -> 5

 

for f(x) = 4x^3 and g(x) = 'squareroot' x^2 + 5 / 3x^2

 

a. 'squareroot' 30/ 75  -500

b. 'squareroot' 6 / 3 + 500

c. 20 'squareroot' 30 / 3

d. 'squareroot' 6 / 3  -500

e. limit does not exist

 Sep 2, 2016
 #1
avatar+129840 
0

lim [ g(x) - f(x)

x -> 5

 

 

g(x)  as x  -> 5   =  √ [5^2 + 5] / [3(5)^2]  =  √30/ 75

 

f(x) as x  -> 5  = 4(5)^3  = 500

 

So

 

lim [ g(x) - f(x)     =    √30/ 75  - 500   →    answer  "a"

x -> 5

 

 

 

cool cool cool

 Sep 2, 2016

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