+0  
 
0
307
1
avatar+314 

I really need help

 Oct 18, 2017
 #1
avatar+98125 
+4

 

We don't know what the periods are, but the graphs appear to be normally situated....thus they are not "flipped over"  which result in both a1 and a2 being negative...so both are positive 

 

However, the amplitude of the sine graph is greater than that of the cosine graph...so...

 

B is the correct answer  →  0 < a2 < a1

 

 

cool cool cool  

 Oct 18, 2017

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