#1**+4 **

We don't know what the periods are, but the graphs appear to be normally situated....thus they are not "flipped over" which result in both a_{1} and a_{2} being negative...so both are positive

However, the amplitude of the sine graph is greater than that of the cosine graph...so...

B is the correct answer → 0 < a_{2} < a_{1}

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CPhill
Oct 18, 2017