#1**+10 **

$$2p^2-3p-54$$

first I would look for 2 numbers that mult to 2*-54=-108

since it mult to a negative one must be positive and the other one negative.

BUT they also have to add to -3 So the 'bigger' one will be neg and they must be close together. (3 apart.)

Now i am just going to 'play' with the factors of 108.

108=4*27 = 4*3*3*3=9*12 BINGO

-12 and +9

NOW

I will split -3p up into -12p+9p

$$\\2p^2-3p-54\\

=2p^2-12p+9p-54\\

$now factorise in pairs$\\

=2p(p-6)+9(p-6)\\

=(2p+9)(p-6)\\$$

And that is it :)

Melody
Apr 1, 2015

#1**+10 **

Best Answer

$$2p^2-3p-54$$

first I would look for 2 numbers that mult to 2*-54=-108

since it mult to a negative one must be positive and the other one negative.

BUT they also have to add to -3 So the 'bigger' one will be neg and they must be close together. (3 apart.)

Now i am just going to 'play' with the factors of 108.

108=4*27 = 4*3*3*3=9*12 BINGO

-12 and +9

NOW

I will split -3p up into -12p+9p

$$\\2p^2-3p-54\\

=2p^2-12p+9p-54\\

$now factorise in pairs$\\

=2p(p-6)+9(p-6)\\

=(2p+9)(p-6)\\$$

And that is it :)

Melody
Apr 1, 2015