how do you find a sequence repesents thit three different numbers like

(4,12)

(5,36)

(6,108)

Guest May 4, 2017

#1**+1 **

(x , y)

(4,12)

(5,36)

(6,108)

Note that we can write this as an exponential function in the form : y = a(b)^x

So we have :

12 = a(b)^4 → a = 12 / (b^4) (1)

36 = a(b)^5 (2)

Sub (1) into (2)

36 = (12 / b^4) b^5 simplify

3 = b

Subbing this into (1), we have that a = 12 / 3^4 = 12/81 = 4/27

So the function is

y = (4/27) (3)^x

CPhill
May 4, 2017

#2**0 **

If you want to know what **sequence** the numbers form, then it is as follows:

4, 12, 5, 36, 6, 108, 7, 324, 8, 972.........etc.

First term goes up by 1, such as 4+1, 5+1, 6+1......etc.

Second term is multiplied by 3, such as 12 x 3, 36 x 3, 108 x 3 .......and so on.

Guest May 4, 2017

#3**+2 **

There is insufficient information in the question,

the quadratic \(\displaystyle f(x) = 24x^{2}-192x +396\)

fits the sequence just as well.

You need to be told what sort of function that you're looking for.

(It's also possible to find an infinite number of cubics, quartics ... etc. as well.)

Guest May 4, 2017