+67 How would you find the derivative of \(\sqrt[x]{x}\)? The derivative rule of \({x}^{a}=a{x}^{a-1}\) gives me the new formula of \(\frac{1}{x}{x}^{\frac{1}{x}-1}\) (because \(\sqrt[x]{x}={x}^{\frac{1}{x}}\)). However, this equation isn't the derivative of \(\sqrt[x]{x}\), and I can't figure out how else you would determine that.
