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how do you find the geometric mean of a pair of numbers and put it in the simplest radical form? (e.g. 3 and 9)

Guest Feb 9, 2015

Best Answer 

 #4
avatar+90023 
+5

The geometric mean of of any set of N numbers is just the nth root of their product =

n√(a*b*c*d*...*n)

 

CPhill  Feb 10, 2015
 #1
avatar+17 
0

Do you mean like "3,5,6,7,9,1 = (Mean) 5.6666666661 = 6?

Fireshot360  Feb 9, 2015
 #2
avatar+93665 
+5

I think that it is         3,x,9

 

$$x/3=9/x

x^2=27

x=
\sqrt{27}=3\sqrt3$$

Melody  Feb 10, 2015
 #3
avatar+20025 
+5

How do you find the geometric mean of a pair of numbers and put it in the simplest radical form? (e.g. 3 and 9)

For instance, the geometric mean of two numbers, say 2 and 8,

is just the square root of their product; that is $$\sqrt{2\cdot 8}=4$$.

$$\small{\text{
The geomeric mean of the pair of numbers 3 and 9 is:
$
\sqrt[2]{3*9}= \sqrt[2]{3}* \sqrt[2]{9}= \sqrt[2]{3}* 3
$
}}$$

See: https://en.wikipedia.org/wiki/Geometric_mean

heureka  Feb 10, 2015
 #4
avatar+90023 
+5
Best Answer

The geometric mean of of any set of N numbers is just the nth root of their product =

n√(a*b*c*d*...*n)

 

CPhill  Feb 10, 2015

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