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# how do you find the geometric mean of a pair of numbers and put it in the simplest radical form? (e.g. 3 and 9)

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how do you find the geometric mean of a pair of numbers and put it in the simplest radical form? (e.g. 3 and 9)

Feb 9, 2015

#4
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The geometric mean of of any set of N numbers is just the nth root of their product =

n√(a*b*c*d*...*n)

Feb 10, 2015

#1
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Do you mean like "3,5,6,7,9,1 = (Mean) 5.6666666661 = 6?

Feb 9, 2015
#2
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I think that it is         3,x,9

$$x/3=9/x x^2=27 x= \sqrt{27}=3\sqrt3$$

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Feb 10, 2015
#3
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How do you find the geometric mean of a pair of numbers and put it in the simplest radical form? (e.g. 3 and 9)

For instance, the geometric mean of two numbers, say 2 and 8,

is just the square root of their product; that is $$\sqrt{2\cdot 8}=4$$.

$$\small{\text{ The geomeric mean of the pair of numbers 3 and 9 is:  \sqrt[2]{3*9}= \sqrt[2]{3}* \sqrt[2]{9}= \sqrt[2]{3}* 3  }}$$

Feb 10, 2015
#4
+94545
+5

The geometric mean of of any set of N numbers is just the nth root of their product =

n√(a*b*c*d*...*n)

CPhill Feb 10, 2015