+0

# How do you solve 4+3x5-6^4/(4+2)^3x2 by simplifying it?

0
391
1

How do you solve 4+3x5-6^4/(4+2)^3x2 by simplifying it?

Guest Jun 10, 2015

#1
+17721
+5

4 + 3·5 - 64/(4 + 2)3·2

First, do what is inside parentheses first:

=  4 + 3·5 - 64/(6)3·2

=  4 + 3·5 - 64/63·2

Next, do exponents:  64  =  1296  and  63  =  216

=  4 + 3·5 - 1296/216·2

Next, do multiplications and divisions from left to right:

=  4 + 15 - 1296/216·2

=  4 + 15 - 6·2

=  4 + 15 - 12

Finally, do additions and subtractions from left to right:

=  19 - 12

=  7

geno3141  Jun 10, 2015
Sort:

#1
+17721
+5

4 + 3·5 - 64/(4 + 2)3·2

First, do what is inside parentheses first:

=  4 + 3·5 - 64/(6)3·2

=  4 + 3·5 - 64/63·2

Next, do exponents:  64  =  1296  and  63  =  216

=  4 + 3·5 - 1296/216·2

Next, do multiplications and divisions from left to right:

=  4 + 15 - 1296/216·2

=  4 + 15 - 6·2

=  4 + 15 - 12

Finally, do additions and subtractions from left to right:

=  19 - 12

=  7

geno3141  Jun 10, 2015

### 36 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details