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How do you solve 4+3x5-6^4/(4+2)^3x2 by simplifying it?

 Jun 10, 2015

Best Answer 

 #1
avatar+17747 
+5

4 + 3·5 - 64/(4 + 2)3·2

First, do what is inside parentheses first:

=  4 + 3·5 - 64/(6)3·2

=  4 + 3·5 - 64/63·2

Next, do exponents:  64  =  1296  and  63  =  216

=  4 + 3·5 - 1296/216·2

Next, do multiplications and divisions from left to right:

=  4 + 15 - 1296/216·2

=  4 + 15 - 6·2

=  4 + 15 - 12

Finally, do additions and subtractions from left to right:

=  19 - 12

=  7

 Jun 10, 2015
 #1
avatar+17747 
+5
Best Answer

4 + 3·5 - 64/(4 + 2)3·2

First, do what is inside parentheses first:

=  4 + 3·5 - 64/(6)3·2

=  4 + 3·5 - 64/63·2

Next, do exponents:  64  =  1296  and  63  =  216

=  4 + 3·5 - 1296/216·2

Next, do multiplications and divisions from left to right:

=  4 + 15 - 1296/216·2

=  4 + 15 - 6·2

=  4 + 15 - 12

Finally, do additions and subtractions from left to right:

=  19 - 12

=  7

geno3141 Jun 10, 2015

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