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How do you solve these using elimination?

 

1,000,000 - 25,000x = y 

and 

600,000 + 10,000x = y

Guest Mar 3, 2017
 #1
avatar+7348 
+5

How do you solve these using elimination?

 

1,000,000 - 25,000x = y 

and 

600,000 + 10,000x = y

 

\(1,000,000 - 25,000x = y \)

\(\underline{600,000 \ + 10,000x = y}\)     subtract

.   \(400,000-35,000x=0\)

 

\(-35,000x=-400,000\)          divide

 

\(x=11\frac{3}{7}\)

 

or

 

\(600,000 + 10,000x = 1,000,000 - 25,000x \)

 

\(10,000x+25,000x=1,000,000-600,000\)

 

\(35,000x=400,000\)

 

\(7x=80\)

 

\(x=11\frac{3}{7}\)

 

\(y=600,000 + 10,000x\)

 

\(y=600,000 + 10,000\times\frac{80}{7}\)

 

\(y=600,000 + 114,285.7\overline{142857}...\)

 

 

\(y= 714,285.7\overline{142857}...\)

 

laugh !

asinus  Mar 3, 2017

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