How do you wright a equation for this? The Hi-Line School is having an all day-school play. The cost of two adult and two children tickets is $24. A child's ticket cost half as much as an adult ticket.
Let C be the cost of a child's ticket.....and 2C be the cost of an adult ticket....then
2 child's tickets cost 2(C) = 2C
And 2 adult tickets cost 2(2C) = 4C
So the total cost is given by
2C + 4C = 24 simplify
6C = 24 divide both sides by 6
C = 4 and the cost of a child's ticket in dollars
And 2(4) = 8 = the cost of an adult ticket in dollars
Just as AmandaXo has found !!!
I don't really know how to write an equation for this, but if the total cost for two adults and two kids is $24 and the child's ticket costs half of the adults ticket then it is 8 dollars for an adult and 4 dollars for a child.
8 goes in 24 three times. So 2 times, for the adult tickets, and then u devide the last one by two, which is 4.
does that make sense?
Hope this helps!!
Let C be the cost of a child's ticket.....and 2C be the cost of an adult ticket....then
2 child's tickets cost 2(C) = 2C
And 2 adult tickets cost 2(2C) = 4C
So the total cost is given by
2C + 4C = 24 simplify
6C = 24 divide both sides by 6
C = 4 and the cost of a child's ticket in dollars
And 2(4) = 8 = the cost of an adult ticket in dollars
Just as AmandaXo has found !!!