how i do this f(x)=x^2(x-3)

buna dimineata

how i do  this f(x)=x^2(x-3)

There is nothing to do.... This is not a question.

you can rearrange it a little if you want but there is no real reason why you would want to.....

\(f(x)=x^2(x-3)\\ f(x)=x^3-3x^2\\\)

hi galeano,

It is evening for me   LOL

Este seara, timp de mine   

ok thanks. but i have to take x-intercepts and y-intercept, then find the vertx, and finally make a graph and drop points. i sorry  for my inglish bad

Hi galeano,

I nearly missed this request for more help.  Next time you would be best to copy the address and paste it into a private message for me :)

Then I will know that you want more help and I will be able to go straight to the question.  :)

f(x)=x^2(x-3)

Ok, I didn't realize that you needed to graph it.  :)

First it will cross the x-axis when f(x)=0

this will happen when x=0 and when x-3=0  which is when x=3

now because it is x^2, that means the graph will only just touch the axis at x=0 and then it will turn around and go back where it came from.

f(x)=x^3-3x^2+0

because it is x^3 the graph will have 3 directions and because it is +x^3  it will start up in the top right hand corner .

So I know a lot about what the graph will look like just by having a quick look.

The y intercept is 0 

To know much more I would need to use calculus.

This is what the graph looks like.

https://www.desmos.com/calculator/despxw3pos