We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
48
4
avatar+1278 

A bookcase is 3 feet high and 3 feet wide. Two braces are going to be built to diagonally cross the back of the case. How long is the piece of wood that is needed to build each brace ?

 

A) 3√3 feet

B) 3√2  feet

C) 3 feet

D) 6 feet

E) 9 feet

 Nov 5, 2019
 #1
avatar+19937 
+1

How would YOU go about solving this?  Any ideas?   Have you tried?  cheeky

 Nov 5, 2019
 #3
avatar+1278 
+1

9 + 9 = x^2      

 

18 = x^2

 

x = 3√2 ft

macabresubwoofer  Nov 5, 2019
 #4
avatar
+1

 

Correctamundo, macabre!  Good work! 

.

Guest Nov 5, 2019
 #2
avatar
0

 

A bookcase is 3 feet high and 3 feet wide. Two braces are going to be built to diagonally cross the back of the case. How long is the piece of wood that is needed to build each brace ?   

 

Each diagonal forms the hypotenuse of a right triangle.  I would use the Pythagoras Theorem to determine its length.  Draw it on paper if you need to.

 

 

.

 Nov 5, 2019

12 Online Users

avatar